complex wsdl types to scala

Main.scala

import scala.xml.XML

object Main extends App {
  def getType(w: String) = w dropWhile ( _ != ':' ) drop(1) capitalize
  
  val xml = XML.loadFile("Sample.wsdl")
  val types = (xml \ "types" \ "schema" \ "complexType")
  
  types map { complextype =>
      println("case class %s(".format(complextype.attribute("name").get))
      println((complextype \ "sequence" \ "element") map { elem =>
              "  val %s: %s = None".
                format (elem.attribute("name").get,
                  getType(elem.attribute("type").getOrElse("xs:any").toString))
            } mkString ",\n")
      println("  )")
    }
}

out.scala

case class login(
  val username: String = None,
  val password: String = None,
  val userType: Int = None
  )

Sample.wsdl

<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions>
    <wsdl:types>
        <xs:schema>
            <xs:complexType name="login">
                <xs:sequence>
                    <xs:element minOccurs="0" name="username" nillable="true" type="xs:string"/>
                    <xs:element minOccurs="0" name="password" nillable="true" type="xs:string"/>
                    <xs:element minOccurs="0" name="userType" type="xs:int"/>
                </xs:sequence>
            </xs:complexType>
        </xs:schema>
    </wsdl:types>
</wsdl:definitions>