Created
June 21, 2020 20:45
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Leetcode #1423: Maximum Points You Can Obtain from Cards (https://interviewrecipes.com/leetcode-1423)
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class Solution { | |
public: | |
int maxScore(vector<int>& cardPoints, int k) { | |
int n = cardPoints.size(); | |
vector<int> cumulativeSumFront(n+1, 0); // For easier indexing, add an extra element. | |
vector<int> cumulativeSumBack(n+1, 0); // For easier indexing, add an extra element. | |
for (int i=0; i<n; i++) { | |
cumulativeSumFront[i+1] = cumulativeSumFront[i] + cardPoints[i]; | |
} | |
for (int i=n-1; i>=0; i--) { | |
cumulativeSumBack[i] = cumulativeSumBack[i+1] + cardPoints[i]; | |
} | |
// Reversing is optional. I reversed it so that it would be easy | |
// to access sum of last (k-i) elements by just indexing at [k-i] | |
// Otherwise, I would have had to index it at [n-k+i] which would | |
// have made it difficult to read. | |
reverse(cumulativeSumBack.begin(), cumulativeSumBack.end()); | |
int answer = 0; | |
for(int i=0; i<=k; i++) { | |
answer = max(answer, | |
cumulativeSumFront[i] // Sum of 'i' cards from the front. | |
+ cumulativeSumBack[k-i]); // Sum of 'k-i' cards from the back. | |
} | |
return answer; | |
} | |
}; |
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