Created
June 22, 2021 14:13
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/** | |
* * Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. | |
* * | |
* * You may assume that each input would have exactly one solution, and you may not use the same element twice. | |
* * | |
* * You can return the answer in any order. | |
* * | |
* * Example 1: | |
* * Input: nums = [2,7,11,15], target = 9 | |
* * Output: [0,1] | |
* * Output: Because nums[0] + nums[1] == 9, we return [0, 1]. | |
* * | |
* * Example 2: | |
* * Input: nums = [3,2,4], target = 6 | |
* * Output: [1,2] | |
* * | |
* * Example 3: | |
* * Input: nums = [3,3], target = 6 | |
* * Output: [0,1] | |
*/ | |
package com.basic.leetcode; | |
import lombok.extern.slf4j.Slf4j; | |
@Slf4j | |
public class TwoSum { | |
public static void main(String[] args) { | |
int[] arrayOfNumbers = {2, 7, 11, 15}; | |
int target = 9; | |
log.info("Finding out two sums for the array {} and target {}. We get {}", arrayOfNumbers, target, | |
twoSums(arrayOfNumbers, target)); | |
} | |
static int[] twoSums(int[] nums, int target) { | |
int[] a = new int[2]; | |
int idx = 0; | |
for (int i = 0; i < nums.length; i++) { | |
for (int j = i + 1; j < nums.length; j++) { | |
if (nums[i] + nums[j] == target) { | |
a[idx] = i; | |
a[idx + 1] = j; | |
} | |
} | |
} | |
return a; | |
} | |
} |
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