gets the top three numbers in an array

topNumbersInArray.js

var input = [6,7,3,8,2,5,8,9,2,3,3,1,4,5,5,5,2,3,5];

console.log(input.join(' '));

function top(arr) {
  var sum = {};
  var temp = arr;
  var top = [null, null, null];
  var first = 0;
  var second = 0;
  var third = 0;

  while (temp.length > 0) {
    var current = temp[0];
    if (!sum[current]) {
      var count = 0;
      count = summary(temp, current);
      temp = remaining(temp, current);

      //console.log('remainig ' + temp);

          sum[current] = count;

          let st = top[0];
          let sd = top[1];
          let th = top[2];

          //console.log(st, sd, th);

          if (count > first) {
            second = first;
            third = second;
            first = count;

            top[2] = sd;
            top[1] = st;
            top[0] = current;

          } else if (count > second) {
            third = second;
            second = count;

            top[2] = sd;
            top[1] = current;


          } else if (count > third) {
            third = count;
            top[2] = current;
          }


    } else {
      temp = [];
    }


  }
  console.log(sum);
  console.log(top);
  //ponderiza(top);
}

function remaining(arr, curr) {
  var newArr = [];

  for (var i = 0; i < arr.length; i++) {
    if (arr[i] != curr) {
      newArr.push(arr[i]);
    }
  }

  return newArr;
}

function summary(arr, curr) {
  var count = 0;
  for (var i = 0; i < arr.length; i++) {
    if (arr[i] == curr) {
      count += 1;
    }
  }

  return count;
}

top(input);