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7D - Palindrome Degree
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#include <algorithm> | |
#include <iostream> | |
#include <unordered_map> | |
#include <unordered_set> | |
#include <numeric> | |
#include <set> | |
#include <sstream> | |
#include <string> | |
#include <vector> | |
#include <math.h> | |
#include <fstream> | |
#include <stack> | |
#include <list> | |
using namespace std; | |
#define LL long long | |
//#define LOCAL | |
string preProcess(string s) { | |
int n = s.length(); | |
if (n == 0) return "^$"; | |
string ret = "^"; | |
for (int i = 0; i < n; i++) | |
ret += "#" + s.substr(i, 1); | |
ret += "#$"; | |
return ret; | |
} | |
int main() | |
{ | |
#ifdef LOCAL | |
std::ifstream in("in.txt"); | |
std::streambuf *cinbuf = std::cin.rdbuf(); //save old buf | |
std::cin.rdbuf(in.rdbuf()); //redirect std::cin to in.txt! | |
#endif | |
string s; | |
cin >> s; | |
int n = s.size(); | |
int *t = new int[n](); | |
//Manacher's algorithm | |
//http://leetcode.com/2011/11/longest-palindromic-substring-part-ii.html | |
string T = preProcess(s); | |
int nt = T.size(); | |
int *P = new int[nt]; | |
int C = 0, R = 0; | |
for (int i = 1; i < nt - 1; ++i) { | |
int i_mirror = 2*C-i; // equals to i' = C - (i-C) | |
P[i] = (R > i) ? min(R-i, P[i_mirror]) : 0; | |
// Attempt to expand palindrome centered at i | |
while (T[i + 1 + P[i]] == T[i - 1 - P[i]]) | |
P[i]++; | |
// If palindrome centered at i expand past R, | |
// adjust center based on expanded palindrome. | |
if (i + P[i] > R) { | |
C = i; | |
R = i + P[i]; | |
} | |
} | |
//set t[i] = 1 if s[0..i] is palindrome | |
for (int i = 1; i < nt - 1; i++) { | |
if (P[i] == i - 1) { | |
t[i - 2] = 1; | |
} | |
} | |
int res = 1; | |
for (int i = 1; i < n; ++i) | |
{ | |
//compute palindrome degree for s[0..i] | |
if (t[(i - 1) / 2] && t[i]) | |
{ | |
t[i] = t[(i - 1) / 2] + 1; | |
} | |
res += t[i]; | |
} | |
cout << res; | |
return 0; | |
} |
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