A simple log-in app in python4android

andlog.py

#some simple login app

from android import Android
import time
import random

a = Android()
p=0
a.dialogCreateHorizontalProgress("Loading App")
a.dialogShow()
while p <= 100:
    prog_bar= random.randrange(1,11)
    a.dialogSetCurrentProgress(p)
    time.sleep(0.2)
    p+=prog_bar
print "Done loading!"
a.dialogDismiss()

print '-'*17
a.dialogCreateAlert("Lex", "Please Sign in")
a.dialogShow()
time.sleep(1.8)
a.dialogDismiss()

#sub challenge
data = {"lexis":"12345","degreat":"andex"}

tries = 3

while tries >= 0:
    if tries == 0:
        print "--Bye bye--"
        break
    a.dialogCreateInput("Enter username","username")
    a.dialogSetPositiveButtonText("OK")
    a.dialogShow()
    user=a.dialogGetResponse().result
    username = user["value"]
    a.dialogCreatePassword()
    a.dialogSetPositiveButtonText("OK")
    a.dialogShow()
    passw = a.dialogGetResponse().result
    password = passw["value"]
    if data.has_key(username):
        if password == data[username]:
            a.dialogCreateAlert("Logged")
            a.dialogShow()
            time.sleep(2)
            a.dialogDismiss()
            tries = -1
            print "--Login success--"
            
        else:
            a.dialogueCreateAlert("Sorry! Try Again")
            a.dialogShow()
            time.sleep(2)
            a.dialogDismiss()
            tries-=1
            
    else:
        a.dialogCreateAlert("Sorry! Try Again")
        a.dialogShow()
        time.sleep(2)
        a.dialogDismiss()
        tries -= 1


#main challenge -- the media player
#quit

This program requires you to install sl4a(scripting layer for android) and py4a(python for android) on your android mobile. The users dictionary can be modified to read login credentials from a txt file.