Created
October 28, 2014 14:38
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naive liune drawing algorithm at all possible angles
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public void drawLine(GL gl, int x1, int y1, int x2, int y2) | |
{ | |
//y = mx + c | |
//m = (change in y)/(change in x) | |
double dy = (y2 - y1); | |
double dx = (x2 - x1); | |
//Stop divide by zero | |
if(dx == 0) | |
dx = 1; | |
double m = dy / dx; | |
//solve(y == m*x + c, c) gives (y - m*x) | |
double c = (y2 - m * x2); | |
if(Math.abs(m) < 1.0) | |
{ | |
//Swap start and end points, because they might be negative | |
int start = (dx < 0) ? (x2) : (x1); | |
int end = (dx < 0) ? (x1) : (x2); | |
for(int x = start; x < end; x++) | |
{ | |
double y = m * x + c; | |
gl.glBegin(GL.GL_POLYGON); | |
this.plotPixel(gl, x, (int)y); | |
gl.glEnd(); | |
} | |
} | |
else | |
{ | |
//Gradient is too high: calculate x instead | |
//Swap start and endpoints, because they might be negative | |
int start = (dy < 0) ? (y2) : (y1); | |
int end = (dy < 0) ? (y1) : (y2); | |
System.out.printf("x: %d, y: %d, %f \r\n", start, end, dy); | |
for(int y = start; y < end; y++) | |
{ | |
//solve(y == m*x + c, x) gives -(c - y)/m | |
double x = -(c - y)/m; | |
System.out.println(x); | |
gl.glBegin(GL.GL_POLYGON); | |
this.plotPixel(gl, (int)x, y); | |
gl.glEnd(); | |
} | |
} | |
} |
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