Cube Expression as a Sequence of Consecutive Odd Numbers

cubeSums

import java.util.Scanner;
public class cubeSums {

	private final static double thirds = 1.0/3.0;
	static String oString = "";

	public static boolean isCube(double c){
		double powerVal = Math.pow(c, thirds);
		if(Math.round(c % powerVal) == 0 && c != 3){
			return true;
		}else{
			return false;
		}
	}
	
	public static void main(String[] args) {
		@SuppressWarnings("resource")
		Scanner input = new Scanner(System.in);
		while(input.hasNextDouble()){
			double number = input.nextDouble();
			oString = "";
			if(number == 1){ oString = "1 = 1"; } else {
				if(isCube(number)){
					oString += (int) number + " = ";
					double cRoot = Math.round(Math.pow(number, thirds));

						int sNum = (int) ((cRoot * cRoot) - cRoot) + 1;
						oString += sNum + " + ";
						for(int i = 1; i <= cRoot - 1; i++){
							if(i == cRoot - 1){
								oString += (sNum + (2 * i));
							}else{
								oString += (sNum + (2 * i)) + " + ";
							}
						}
				}else{
					oString = "NOT CUBE";
				}
			}
			System.out.println(oString + "\n");
		}

	}

}