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#! /usr/bin/env python3 | |
"""Is this a bug in lightfm's precision_at_k function? | |
If there are #entries < k for a particular user, it seems as if that user can _never_ have a precision | |
> (#positive_interactions / k) for that user. So, the maximum precision is _not_ in fact 1.0, it's whatever the average | |
of _all_ the (#positive_interactions / k) values are throughout the entire training set. | |
I have a proposed solution at the end. I wonder if it works. | |
""" | |
import numpy as np | |
from scipy.sparse import csr_matrix | |
from lightfm import LightFM | |
from lightfm.evaluation import precision_at_k | |
def main(): | |
realdata = [ | |
[5, 0, 0, 0, 0, 0], | |
[5, 5, 0, 0, 0, 0], | |
[5, 5, 5, 0, 0, 0], | |
[5, 5, 5, 5, 0, 0], | |
[5, 5, 5, 5, 5, 0], | |
[5, 5, 5, 5, 5, 5], | |
] | |
data = { | |
"train": csr_matrix(realdata), | |
"test": csr_matrix(realdata), | |
} | |
model = LightFM(loss="warp") | |
model.fit(data["train"], epochs=300, num_threads=2) | |
rank = model.predict_rank(data["train"]) | |
print(rank.todense()) | |
print(data["train"].todense()) | |
precision = precision_at_k(model, data["train"], k=5) | |
print(precision) | |
print("Train precision: %.2f" % (precision.mean(),)) | |
# Proposed solution: | |
k = 5 | |
ranks = model.predict_rank(data["train"]) | |
ranks.data = np.less(ranks.data, k, ranks.data) | |
denominator = np.clip((data["train"] != 0).astype(np.float).sum(axis=1), 1, k) | |
print(denominator) | |
precision = np.squeeze(np.array(ranks.sum(axis=1)) / denominator) | |
print(precision) | |
if __name__ == "__main__": | |
main() |
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