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#include <iostream> | |
#include <vector> | |
#include <algorithm> | |
#include <assert.h> | |
using namespace std; | |
int romeEval(const int a, const int b) { | |
if (a < b) { | |
return b - a; | |
} else { | |
return b + a; | |
} | |
} | |
int evalChar(const char c) { | |
switch(c) { | |
case 'I': | |
return 1; | |
case 'V': | |
return 5; | |
case 'X': | |
return 10; | |
case 'L': | |
return 50; | |
case 'C': | |
return 100; | |
} | |
assert(false); | |
return -1; | |
} | |
const int NUM_VAL = 5001; | |
struct arr { | |
int size; | |
int vals[NUM_VAL]; | |
}; | |
// segLen, start | |
arr dp[51][50]; | |
void push(const int val, arr &a) { | |
a.vals[a.size] = val; | |
a.size++; | |
} | |
void init(arr &a) { | |
memset(a.vals, -1, NUM_VAL); | |
a.size = 0; | |
} | |
// visited set | |
bool bs[NUM_VAL]; | |
void merge_subseq(const int segLen, const int start) { | |
// k is the splitting point for recursion | |
for (int k = 1; k < segLen; k++) { | |
int s1 = dp[k][start].size; | |
int s2 = dp[segLen - k][start + k].size; | |
for(int i = 0; i < s1; i++) { | |
for(int j = 0; j < s2; j++) { | |
int res = romeEval(dp[k][start].vals[i], dp[segLen - k][start + k].vals[j]); | |
if (! bs[res]) { | |
push(res, dp[segLen][start]); | |
bs[res] = true; | |
} | |
} | |
} | |
} | |
} | |
int main () { | |
for(int t = 1; ; t++) { | |
string seq; | |
cin >> seq; | |
if (seq == "0") break; | |
int n = seq.size(); | |
// evaluate single characters | |
for (int start = 0; start < n; start++) { | |
int res = evalChar(seq[start]); | |
init(dp[1][start]); | |
push(res, dp[1][start]); | |
} | |
// max 49 of these | |
for(int segLen = 2; segLen <= n; segLen++) { | |
// max 49 of these | |
for (int start = 0; start <= n - segLen; start++) { | |
init(dp[segLen][start]); | |
// clear visited set after every segment size | |
bzero(bs, NUM_VAL); | |
merge_subseq(segLen, start); | |
} | |
} | |
// get final values into vector | |
vector<int> fv; | |
for (int i = 0; i < dp[n][0].size; i++) { | |
fv.push_back(dp[n][0].vals[i]); | |
} | |
sort(fv.begin(), fv.end()); | |
cout << "Case " << t <<":"; | |
for (int i = 0; i < fv.size(); i++) { | |
cout << " " << fv[i]; | |
} | |
cout << endl; | |
} | |
return 0; | |
} |
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