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November 10, 2018 05:36
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simple devide and conquer distance algoritm example with matplotlib
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# 분할정복 가장 가까운 점들 사이의 거리 구하는 Algorithm | |
import matplotlib.pyplot as plt | |
def distance(a, b, c, d): | |
result = pow((pow(c - a, 2) + pow(d - b, 2)), 0.5) | |
return result | |
def searching(alist): | |
min = distance(alist[0][1], alist[0][2], | |
alist[1][1], alist[1][2]) | |
for i in range(1, len(alist)): | |
if min > distance(alist[i - 1][1], alist[i - 1][2], | |
alist[i][1], alist[i][2]): | |
min = distance(alist[i - 1][1], alist[i - 1][2], | |
alist[i][1], alist[i][2]) | |
return min | |
def minimum(a, b): | |
if a > b: | |
return b | |
else: | |
return a | |
def mid_search(minusy, plus, min): | |
for i in range(len(plus)): | |
if (plus[i][1] < min) and ((plus[i][2] < minusy + min) or (plus[i][2] > minusy - min)): | |
return plus[i] | |
else: | |
return min | |
data_tuples = [('A', -8, 5), | |
('B', -5, -3), | |
('C', 1, 3), | |
('D', 3, -6), | |
('E', 6, 0), | |
('F', 8, 8), | |
('G', -1, 3)] | |
kbs = [(-8, -5, 1, 3, 6, 8, -1)] | |
mbc = [(5, -3, 3, -6, 0, 8, 3)] | |
list = sorted(data_tuples, key=lambda vertices: vertices[1]) | |
plus = [] | |
minus = [] | |
for i in range(0, len(list)): | |
if list[i][1] >= 0: | |
plus.append(list[i]) | |
else: | |
minus.append(list[i]) | |
print(plus) | |
print(minus) | |
a = searching(plus) | |
b = searching(minus) | |
print("Left : ", a) | |
print("Right : ", b) | |
mini = minimum(a, b) | |
minim = [] | |
for i in range(len(minus)): | |
c = int(minus[i][2]) | |
minim = mid_search(c, plus, mini) | |
for i in range(0, len(minus)): | |
if distance(minus[i][1], minus[i][2], minim[1], minim[2]) < mini: | |
print("minimum value : ", distance(minus[i][1], minus[i][2], minim[1], minim[2])) | |
plt.figure() | |
plt.axvline(x=0, color='b', linestyle='-', linewidth=3) | |
plt.scatter(kbs, mbc) | |
plt.show() |
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