Java XSL transform w/ parameters only

out.log

<?xml version="1.0" encoding="UTF-8"?><test>hello world</test>
Process finished with exit code 0

Params.java

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import java.io.File;

public class Params {
    public static void main(String[] args) {
        try {
            // I/O
            DOMSource input = new DOMSource();
            StreamSource xsl = new StreamSource(new File("params.xsl"));
            StreamResult result = new StreamResult(System.out);

            // Transformation
            TransformerFactory factory = TransformerFactory.newInstance();
            Transformer transformer = factory.newTransformer(xsl);
            transformer.setParameter("test", "hello world");
            transformer.transform(input, result);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

params.xsl

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:param name="test"/>
    <xsl:template match="/">
        <test>
            <xsl:value-of select="$test"/>
        </test>
    </xsl:template>
</xsl:stylesheet>