Created
April 5, 2013 19:02
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create table JobHistory ( | |
jobid integer not null auto_increment, | |
jobtitle varchar(32) not null, | |
salary int not null, | |
startdate date not null, | |
enddate date null, | |
primary key (jobid) | |
); | |
INSERT INTO `JobHistory` (`jobid`, `jobtitle`, `employee`, `salary`, `startdate`, `enddate`) | |
VALUES | |
(1,'Newspaper Delivery','joe',3000,'1994-04-12','1998-08-30'), | |
(2,'Restaurant Server','joe',12000,'1998-10-05','1999-05-01'), | |
(3,'Restaurant Server','joe',17000,'1999-06-03','1999-08-25'), | |
(4,'Research Assistant','joe',13000,'1999-09-06','2000-12-05'), | |
(5,'Restaurant Server','joe',14500,'2001-05-29','2001-08-31'); | |
-- Finding Joe's maximum salary is easy | |
select max(salary) | |
from JobHistory | |
where employee = 'joe'; | |
-- How about finding the job where Joe made the most money? | |
-- Subqueries are lame. | |
select * | |
from JobHistory | |
where employee = 'joe' and salary = (select max(salary) from JobHistory where employee = 'joe'); | |
-- Use a reflexive outer join with an inequality condition | |
select J1.* | |
from JobHistory J1 left join JobHistory J2 on (J1.employee = J2.employee and J1.salary < J2.salary) | |
where J2.jobid is null; | |
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