Brendan Magee brendaneamon

## keybase.md

      
              1 file
            
          
              0 forks
            
          
              0 comments
            
          
              0 stars
            
          
                brendaneamon
                / keybase.md
            
            
              Created
              June 21, 2019 23:08
            
              
                Keybase proof of identity
              
          
    Keybase proof

I hereby claim:

I am brendaneamon on github.
I am brendan_eamon (https://keybase.io/brendan_eamon) on keybase.
I have a public key ASAhnd2r4rESFuO0fXCw6iPqCage7E9XA4FFofI_HVYF_go

To claim this, I am signing this object:

  
## getFibonacci.js
'use strict'

function getFibonacciNumber (pos, cache = [1, 1]) {
  if (cache[pos - 1]) {
    return cache[pos - 1]
  }

  const next = cache[cache.length - 2] + cache[cache.length - 1]

  return getFibonacciNumber(pos, [...cache, next])

## getAddendPairs.js
'use strict'

function getAddendPairs(numArray, sum) {
  let difference
  return numArray.reduce((acc, num) => {
    difference = sum - num
    if (!acc.map.has(num)) {
      acc.map.set(num, true)
    }

## getMeanMedianMode.js
'use strict'

function getMean (numbers) {
  return numbers.reduce((acc, num) => {
    return acc += num
  }, 0) / numbers.length
}

function getMedian (numbers) {
  const sorted = [...numbers].sort((a, b) => a - b)
	'use strict'

	function getFibonacciNumber (pos, cache = [1, 1]) {
	if (cache[pos - 1]) {
	return cache[pos - 1]
	}

	const next = cache[cache.length - 2] + cache[cache.length - 1]

	return getFibonacciNumber(pos, [...cache, next])
	'use strict'

	function getAddendPairs(numArray, sum) {
	let difference
	return numArray.reduce((acc, num) => {
	difference = sum - num
	if (!acc.map.has(num)) {
	acc.map.set(num, true)
	}
	'use strict'

	function getMean (numbers) {
	return numbers.reduce((acc, num) => {
	return acc += num
	}, 0) / numbers.length
	}

	function getMedian (numbers) {
	const sorted = [...numbers].sort((a, b) => a - b)