Add operations to and solve: 10 9 8 7 6 5 4 3 2 1 = 2014

gistfile1.sh

#!/bin/bash
s=$1
e=$[ $s + 1 ]
for a in $(seq $(echo "4^8 * $s" | bc -l) $(echo "4^8 * $e" | bc -l)); do
        n=$(echo "obase=4;$a" | bc)
        f=$(
                ( for b in $(seq 1 $[ 9 - ${#n} ]); do
                        printf "0"; done; echo "$n"
                ) | sed -e 's/\(.\)/\1\n/g' | tr '0123' '+\-*/' | for a in {10..1}; do
                        read o
                        printf "$a $o "
                done
                echo
        )
        printf "$f= "
        echo "$f" | bc -l
done

Usage:
./2014 0 > out.0
./2014 1 > out.1
./2014 2 > out.2
./2014 3 > out.3

10 * 9 * 8 * 7 / 6 / 5 * 4 * 3 - 2 - 1 = 2013
10 * 9 * 8 * 7 / 6 / 5 * 4 * 3 - 2 * 1 = 2014
10 * 9 * 8 * 7 / 6 / 5 * 4 * 3 - 2 / 1 = 2014
10 * 9 * 8 * 7 / 6 / 5 * 4 * 3 - 2 + 1 = 2015
10 * 9 * 8 * 7 / 6 / 5 * 4 * 3 + 2 - 1 = 2017