matrix multiplication: numba cuda vs numpy

gistfile1.txt

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 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Matrix multiplication"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Numba GPU"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 37,
   "metadata": {},
   "outputs": [],
   "source": [
    "import numpy as np\n",
    "from numba import cuda\n",
    "@cuda.jit('void( float64 [ : , : ] , float64 [ : , : ] , float64 [ : , : ] , int32 )')\n",
    "def cu_matmul(a , b, c , n) :\n",
    "    x, y = cuda.grid (2)\n",
    "    if (x >= n) or (y >= n) :\n",
    "        return\n",
    "    c[x, y] = 0\n",
    "    for i in range(n) :\n",
    "        c[x, y] += a[x, i ] * b[ i , y]\n",
    "        "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 40,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "14.7 ms ± 163 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)\n"
     ]
    }
   ],
   "source": [
    "device = cuda.get_current_device()\n",
    "tpb = device.WARP_SIZE\n",
    "n = 320\n",
    "bpg = (n+tpb-1)//tpb\n",
    "grid_dim = (bpg, bpg)\n",
    "block_dim = (tpb , tpb)\n",
    "A = np.random.random((n, n ) ).astype (np. float64 )\n",
    "B = np.random.random((n, n ) ).astype (np. float64 )\n",
    "C = np.empty((n, n) , dtype=np.float64 )\n",
    "dev_A = cuda.to_device(A)\n",
    "dev_B = cuda.to_device(B)\n",
    "dev_C = cuda.to_device(C, copy=False )\n",
    "result_cuda = %timeit -o cu_matmul[grid_dim , block_dim](dev_A, dev_B, dev_C, n)\n",
    "dev_C. copy_to_host(C)\n",
    "assert (np. allclose (np. dot(A, B) , C))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Numpy"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 40,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "525 µs ± 16.4 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)\n"
     ]
    }
   ],
   "source": [
    "%timeit C = np.dot(A, B)"
   ]
  }
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matmul2.ipynb