My Code Signal Palindrome Rearranging Solution.

palindromeRearranging.js

function palindromeRearranging(inputString) {
  const charCounts = [...inputString].reduce((counts, char) => {
      counts[char] = counts[char] ? counts[char] + 1 : 1;
      return counts;
  }, {});
  
  return Object.values(charCounts).filter(count => count % 2 !== 0).length <= 1;
}

// First get the character count for each character in the string and store it in an object.

// The string can only be a palindrome if either the count of ALL characters is even 
// or if the count of ONLY ONE character is odd.

// Filter the object values down to just the odd character counts. 
// If the resulting array's length is 0 or 1, the string can be a palindrome. 

this is cool