Golang SOAP Request Example

main.go

package main

import (
	"bytes"
	"crypto/tls"
	"encoding/xml"
	"fmt"
	"io/ioutil"
	"net/http"
	"strings"
)

type SoapHeader struct {
	XMLName xml.Name `xml:"x:Header"`
}

type SoapBody struct {
	XMLName xml.Name `xml:"x:Body"`
	Request interface{}
}

type SoapRoot struct {
	XMLName xml.Name `xml:"x:Envelope"`
	X       string   `xml:"xmlns:x,attr"`
	Sch     string   `xml:"xmlns:sch,attr"`
	Header  SoapHeader
	Body    SoapBody
}

type GetCitiesRequest struct {
	XMLName xml.Name `xml:"sch:GetCitiesRequest"`
}

type GetCitiesResponse struct {
	XMLName xml.Name `xml:"ns3:GetCitiesResponse"`
	result  struct{} `xml:result`
	cities  struct{} `xml:cities`
}

func SoapCall(service string, request interface{}) string {
	var root = SoapRoot{}
	root.X = "http://schemas.xmlsoap.org/soap/envelope/"
	root.Sch = "http://www.n11.com/ws/schemas"
	root.Header = SoapHeader{}
	root.Body = SoapBody{}
	root.Body.Request = request

	out, _ := xml.MarshalIndent(&root, " ", "  ")
	body := string(out)

	client := &http.Client{
		Transport: &http.Transport{
			TLSClientConfig: &tls.Config{
				InsecureSkipVerify: true,
			},
		},
	}
	response, err := client.Post(service, "text/xml", bytes.NewBufferString(body))

	if err != nil {
		fmt.Println(err)
	}
	defer response.Body.Close()

	content, _ := ioutil.ReadAll(response.Body)
	s := strings.TrimSpace(string(content))
	return s
}

func main() {
	SoapCall("https://api.n11.com/ws/CityService.wsdl", GetCitiesRequest{})
}

Merhaba, gelen response'u nasıl parse edebiliriz?

Merhaba, gelen response'u nasıl parse edebiliriz?

buroz/gon11 burada çalışan bir örnek bulunmakta onun üzerinden gidersen daha rahat edebilirsin. Yine yardım gerekirse seve seve ederim mail atman yeterli.

getting Authentication failed

getting Authentication failed

You have to pass username and password inside the body

Thank for the insight. Helped a lot.

https://user:password@api.n11.com/ws/CityService.wsdl