return.scala

object TestReturn {
    def t(n: Int): Boolean = {
        (1 to n).map(x => {
            if (x > 5) return true
            false
        }).exists(_ == true)
    }
}
object TestReturn2 {
    def t(n: Int): Boolean = {
        (1 to n).map(x =>
            if (x > 5) {
                true
            } else {
                false
            }
        ).exists(_ == true)
    }
}

also notice how the compiled code isn't entirely what we want, because return bubbles up into t and not into the anonymous function of map, so the result might not be correct

Here's an example of when it works not the way we expected

object TestReturn {
    def t(n: Int): Boolean = {
        (1 to n).map(x => {
            if (x == 5) return false
            true
        }).last
    }
}
object TestReturn2 {
    def t(n: Int): Boolean = {
        (1 to n).map(x =>
            if (x == 5) {
                false
            } else {
                true
            }
        ).last
    }
}

scala> object TestReturn {
     |     def t(n: Int): Boolean = {
     |         (1 to n).map(x => {
     |             if (x == 5) return false
     |             true
     |         }).last
     |     }
     | }
defined object TestReturn

scala> TestReturn.t(10)
res0: Boolean = false

But it should've returned true since we're past 5

scala> object TestReturn2 {
     |     def t(n: Int): Boolean = {
     |         (1 to n).map(x =>
     |             if (x == 5) {
     |                 false
     |             } else {
     |                 true
     |             }
     |         ).last
     |     }
     | }
defined object TestReturn2

scala> TestReturn2.t(10)
res1: Boolean = true

And this returns correct result, since it actually goes all the way to the last element