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graph_problem
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#!/bin/python3 | |
import sys | |
#functions | |
def BFS(G, s): | |
explored = [] | |
queue = [s] | |
c = 0 | |
while queue: | |
u = queue.pop() | |
if u not in explored: | |
explored.append(u) | |
neighbours = G[u] | |
for neighbour in neighbours: | |
queue.append(neighbour) | |
#print(explored) | |
return explored | |
land = {} | |
q = int(input().strip()) | |
for a0 in range(q): | |
n, m, x, y = input().strip().split(' ') | |
n, m, x, y = [int(n), int(m), int(x), int(y)] | |
for a1 in range(m): | |
city_1, city_2 = input().strip().split(' ') | |
city_1, city_2 = [int(city_1), int(city_2)] | |
#print(city_1, city_2) | |
#insertar ciudades en el grafo | |
if city_1 in land: | |
if not land[city_1]: | |
land[city_1] = [] | |
land[city_1].append(city_2) | |
else: | |
land[city_1].append(city_2) | |
else: | |
land[city_1] = [] | |
land[city_1].append(city_2) | |
if city_2 in land: | |
if not land[city_2]: | |
land[city_2] = [] | |
land[city_2].append(city_1) | |
else: | |
land[city_2].append(city_1) | |
else: | |
land[city_2] = [] | |
first = True | |
towns = [] | |
for k, v in land.items(): | |
if first: | |
towns.append(BFS(land, k)) | |
first = False | |
print(k, BFS(land, k)) | |
if k not in BFS(land, k - 1 ): | |
first = True | |
print(towns) | |
#print(land ) | |
land = {} |
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