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bit operations of two numbers
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#!/bin/bash | |
usage() | |
{ | |
echo "bit operations of two numbers" | |
echo | |
echo "Usage: $(basename $0) NUM1 OPS NUM2 [d]" | |
echo "OPS: a(&, and), o(|, or), x(^, xor), l(<<, left), r(>>, right)" | |
echo "d means result will be dec, default is hex" | |
exit | |
} | |
if [ "$#" -lt 3 ] || [ "$#" -gt 4 ] || [[ "$2" != [aoxlr] ]]; then | |
usage | |
fi | |
if [ "$4" = "d" ]; then | |
echo -n "dec: " | |
if [ "$2" = "a" ]; then | |
printf '%d\n' "$(( $1 & $3 ))" | |
elif [ "$2" = "o" ]; then | |
printf '%d\n' "$(( $1 | $3 ))" | |
elif [ "$2" = "x" ]; then | |
printf '%d\n' "$(( $1 ^ $3 ))" | |
elif [ "$2" = "l" ]; then | |
printf '%d\n' "$(( $1 << $3 ))" | |
elif [ "$2" = "r" ]; then | |
printf '%d\n' "$(( $1 >> $3 ))" | |
fi | |
elif [ "$4" = "" ]; then | |
echo -n "hex: " | |
if [ "$2" = "a" ]; then | |
printf '%X\n' "$(( $1 & $3 ))" | |
elif [ "$2" = "o" ]; then | |
printf '%X\n' "$(( $1 | $3 ))" | |
elif [ "$2" = "x" ]; then | |
printf '%X\n' "$(( $1 ^ $3 ))" | |
elif [ "$2" = "l" ]; then | |
printf '%X\n' "$(( $1 << $3 ))" | |
elif [ "$2" = "r" ]; then | |
printf '%X\n' "$(( $1 >> $3 ))" | |
fi | |
else | |
usage | |
fi |
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