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Merge Arrays in one with ES6 Array spread
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const arr1 = [1,2,3] | |
const arr2 = [4,5,6] | |
const arr3 = [...arr1, ...arr2] //arr3 ==> [1,2,3,4,5,6] |
var odd = [
{ name : "1", arr: "in odd" },
{ name : "3", arr: "in odd" }
];
var even = [
{ name : "1", arr: "in even" },
{ name : "2", arr: "in even" },
{ name : "4", arr: "in even" }
];
// ----
// ES5 using Array.filter and Array.find
function merge(a, b, prop){
var reduced = a.filter(function(aitem){
return ! b.find(function(bitem){
return aitem[prop] === bitem[prop];
});
});
return reduced.concat(b);
}
console.log( "ES5", merge(odd, even, "name") );
// ----
// ES6 arrow functions
function merge(a, b, prop){
var reduced = a.filter( aitem => ! b.find ( bitem => aitem[prop] === bitem[prop]) )
return reduced.concat(b);
}
console.log( "ES6", merge(odd, even, "name") );
// ----
// ES6 one-liner
var merge = (a, b, p) => a.filter( aa => ! b.find ( bb => aa[p] === bb[p]) ).concat(b);
console.log( "ES6 one-liner", merge(odd, even, "name") );
// Results
// ( stuff in the "b" array replaces things in the "a" array )
// [
// {
// "name": "3",
// "arr": "in odd"
// },
// {
// "name": "1",
// "arr": "in even"
// },
// {
// "name": "2",
// "arr": "in even"
// },
// {
// "name": "4",
// "arr": "in even"
// }
// ]
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https://gist.github.com/yesvods/51af798dd1e7058625f4#gistcomment-2365119