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@cAstraea
Created January 31, 2017 10:36
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javascript solution, Finds the minimum number of moves required to rearrange the tanks so that each row and each column contains a single tank, and one such shortest sequence of moves
process.stdin.resume();
process.stdin.setEncoding('ascii');
let input_stdin = '';
let input_stdin_array = '';
let input_currentline = 0;
process.stdin.on('data', (data) => {
input_stdin += data;
});
process.stdin.on('end', () => {
input_stdin_array = input_stdin.split('\n');
main();
});
function readLine() {
return input_stdin_array[input_currentline++];
}
// ///////////// ignore above this line ////////////////////
const resultArray = [];
const pairR = {
int: 0,
char: ''
};
const pairC = {
int: 0,
char: ''
};
const index = [];
function deployRooks(roworcolumn, numberofRooks, X, Y) {
for (let i = 0; i < numberofRooks; ++i) {
index[i] = i;
}
// sort
for (let i = 0; i < numberofRooks; ++i) {
for (let j = i + 1; j < numberofRooks; ++j) {
if (roworcolumn[j] < roworcolumn[i]) {
const tmp = roworcolumn[j];
roworcolumn[j] = roworcolumn[i];
roworcolumn[i] = tmp;
const tmpIndex = index[j];
index[j] = index[i];
index[i] = tmpIndex;
}
}
}
// move up / left
for (let i = 0; i < numberofRooks; ++i) {
for (; roworcolumn[i] > i; --roworcolumn[i]) {
pairR.int = index[i] + 1;
pairR.char = X;
resultArray.push(pairR);
}
}
//move down / right
for (let i2 = numberofRooks - 1; i2 >= 0; --i2) {
for (; roworcolumn[i2] < i2; ++roworcolumn[i2]) {
pairC.int = index[i2] + 1;
pairC.char = Y;
resultArray.push(pairC);
}
}
}
function main() {
// write your code here.
// call `readLine()` to read a line.
// use console.log() to write to stdout
const a = parseInt(readLine(), 10);
const rows = [];
const columns = [];
for (let i = 0; i < a; ++i) {
const c = readLine().split(' ');
rows.push(c[0]);
columns.push(c[1]);
--rows[i];
--columns[i];
}
deployRooks(rows, a, 'Up', 'Down'); // deploys rows
deployRooks(columns, a, 'Left', 'Right'); // deploy on columns
//console.log(resultArray);
console.log(resultArray.length);
}
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