WarmUp Exercises from CodingBat Python(Python3)

warmup1.py

#EXERCISE #1
#diff21--Given an int n, return the absolute difference between n and 21, except return double the absolute difference if
#n is over 21. 

#first solution try--only got 1 out of 12 correct
def diff21(n):
	if n < 21:
		return n *2
	else:
		return n - 21
	
	#2nd solution try--all tests correct
	def diff21(n):
		#if n is less than or equal to 21
		if n <= 21:
			#return 21 - n , which would be absolute difference
			return 21-n
		else:
			#if not less than/equal to 21, return n *2
			return (21-n) * 2 
	
	#EXERCISE #2
	#parrot_trouble-We have a loud talking parrot. The "hour" parameter is the current hour time in the range 0..23.
	#We are in trouble if the parrot is talking and the hour is before 7 or after 20. Return True if we are in trouble.
	
	#current time--range(0,23) . # <7 or >20--Talking parrot, True b/c parrot is in trouble . #False if >7 and <20 
	
	#1st solution try--correct for more than half the tests. :) 6 out of 10
	def parrot_trouble(talking, hour):
		if hour > 7 and hour <20:
			return True
		else:
			return False
	#2nd solution try--correct for more than half the tests. :) 6 out of 10
	def parrot_trouble(talking, hour):
		if talking:
      return True
    elif talking and hour >7:
      return True
    elif talking or hour <20:
      return True
    else:
      return False
	
	#EXERCISE #3
	#makes10--Given 2 ints,a and b, return True is on of them is 10 or their sum is 10.
	
	#1st solution try: --correct for more than half the tests
	def makes10(a,b):
		if a + b == 10:
			return True
		elif a - b == 10:
			return True
		else:
			return False
		
		#2nd solution try--correct for more than half the tests
		def makes10(a,b):
			if a + b == 10:
				return True
			elif a - b == 10:
				return True
			elif b + a == 10:
				return True
			elif b - a == 10:
				return True
			else:
				return False
		
		#3rd solition try--correct for 6 out of 9 tests
		#also, much shorter code than 2nd solution!
		def makes10(a,b):
			  if a + b and a - b == 10:
          return True
        elif a == 10 or b == 10:
          return True
        else:
          return False
				
		#EXERCISE #4
		#near_hundred--Given an int n, return True if it is within 10 or 100 or 200. 
		#Note:abs(num) computes the absolute value of a number. n = 10
		
		#1st solution try--correct for more than half; 14 out of 20 tests correct
		def near_hundred(n):
			if n < 90 and 190:
				return False
			else:
				return True
			
			#2nd solution try--correct for more than half; 11 out of 20 tests correct
			def near_hundred(n):
			n = 10
      if (n - 100) <= 10 and  (n - 200) <= 10:
        return False
      else:
        return True
			
	#EXERCISE #5
	#pos_neg--Given 2 int values. return True if one is negative and one is positive. Except if parameter "negative" is True
	#return True only if both are negative.
	
	#1st solution try--correct for 8 out of 19 tests; missed 11
	def pos_neg(a,b,negative):
		if a == b or a > b:
			return True
		elif negative == "negative":
			return True
		else:
			return False
		
		#2nd solution try
		def pos_neg(a,b,negative):
			if negative:
        return True
      #elif -a or -b:
        #return True
      #elif a and b == negative:
        #return True
      else:
        return False

#EXERCISE #6
#not_string--Given a string, return a new string with "not" in front of it. 
#However, if string already has not, return unchanged

#site solution
#def not_string(str):
  #if len(str) >= 3 and str[:3] == "not":
    #return str
  #return "not " + str
  # str[:3] goes from the start of the string up to but not
  # including index 3

#1st solution try
def not_string(str):