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Rounding multiple times while not losing remainders in Javascript
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/* | |
* Return the rounded number and the new remainder using past remainder. | |
* | |
* @param {number} number The number that needs to be rounded | |
* @param {number} priorRemainder The remainder that is left over from last time that needs to be added to the calculation | |
*/ | |
function multiRound(number, priorRemainder) { | |
var floored = Math.floor(number + priorRemainder); | |
var difference = (number + priorRemainder) - floored; | |
return { | |
number : floored, | |
remainder : difference | |
}; | |
} | |
/* | |
* Demonstrate rounding of an array | |
* | |
* @param {Array} arr A list of numbers to be rounded | |
* @returns {Array} New array with adjusted numbers | |
*/ | |
function roundArray(arr) { | |
var globalRemainder = 0; | |
return arr.map(function(item){ | |
var result = multiRound(item, globalRemainder); | |
globalRemainder = result.remainder; | |
return result.number | |
}); | |
} | |
/* Now try it */ | |
var arr = [1.1, 2.2, 3.3, 4.4, 5.5, 6.6]; | |
var newArr = roundArray(arr); | |
/* Result should be [1, 2, 3, 5, 5, 7] */ |
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