Try with Timeout

there_is_no_try.py

#code gist, courtesy of Jabba Laci
#sauce: https://pythonadventures.wordpress.com/2012/12/08/raise-a-timeout-exception-after-x-seconds/
import signal
import time
 
def test_request(arg=None):
    """Your http request."""
    time.sleep(2)
    return arg
 
class Timeout():
    """Timeout class using ALARM signal."""
    class Timeout(Exception):
        pass
 
    def __init__(self, sec):
        self.sec = sec
 
    def __enter__(self):
        signal.signal(signal.SIGALRM, self.raise_timeout)
        signal.alarm(self.sec)
 
    def __exit__(self, *args):
        signal.alarm(0)    # disable alarm
 
    def raise_timeout(self, *args):
        raise Timeout.Timeout()
 
def main():
    # Run block of code with timeouts
    try:
        with Timeout(3):
            print(test_request("Request 1"))
        with Timeout(1):
            print(test_request("Request 2"))
    except Timeout.Timeout:
        print("Timeout")
 
#############################################################################
 
if __name__ == "__main__":
    main()

I use your code to hit a API on Django, in order to pass if I do not get a response within one second or so. And I got the following error:

ERROR MESSAGE: <type 'exceptions.ValueError'>
signal only works in main thread

Do you have any idea?

@tnajun sorry for the late reply. Unfortunately, I'm not familiar with the Django framework, so I probably don't quite have enough context to understand your problem. Though, based on the error alone, it seems you're passing the correct data type, just not the correct value. Let me know if you ever managed to resolve your issue!