Working code: https://codesandbox.io/s/ancient-snowflake-b8keo
Created
November 20, 2019 18:01
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Flatten an array in TypeScript
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import { flatten, flattenShort } from "./flatten"; | |
describe("flatten tests (iterative implementation)", () => { | |
it("should work well with flat arrays", () => { | |
const actual = flatten([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]); | |
const expected = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; | |
expect(actual).toEqual(expected); | |
}); | |
it("should flatten arbitrary nested arrays", () => { | |
const actual = flatten([[1, 2, [3]], 4]); | |
const expected = [1, 2, 3, 4]; | |
expect(actual).toEqual(expected); | |
}); | |
}); | |
describe("flattenShort tests (recursive implementation)", () => { | |
it("should work well with flat arrays", () => { | |
const actual = flattenShort([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]); | |
const expected = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; | |
expect(actual).toEqual(expected); | |
}); | |
it("should flatten arbitrary nested arrays", () => { | |
const actual = flattenShort([[1, 2, [3]], 4]); | |
const expected = [1, 2, 3, 4]; | |
expect(actual).toEqual(expected); | |
}); | |
}); |
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/* Once TypeScript releases recursive types https://github.com/microsoft/TypeScript/pull/33050 | |
we could implement the NestedIntegerArray as follows: | |
export type NestedIntegerArray = Array<number | NestedIntegerArray>; | |
*/ | |
export type NestedIntegerArray = Array<any>; | |
/** | |
* Flatten an array of arbitrarily nested arrays of integers into a flat array of integers (iterative implementation). | |
* | |
* @typedef {Array<number|NestedIntegerArray>} NestedIntegerArray | |
* @param {NestedIntegerArray} arr - An array of arbitrarily nested arrays of integers | |
* @return {Array<number>} A flat array of integers | |
* | |
* @example | |
* | |
* flatten([[1,2,[3]],4]) -> [1,2,3,4] | |
*/ | |
export function flatten(arr: NestedIntegerArray): Array<number> { | |
let result = []; | |
let stack = [arr]; | |
let indexes = [0]; | |
while (stack.length > 0) { | |
let current = stack.pop(); | |
let currentIndex = indexes.pop(); | |
for (let i = currentIndex, len = current.length; i < len; i++) { | |
let element = current[i]; | |
if (Array.isArray(element)) { | |
stack.push(current, element); | |
indexes.push(i + 1, 0); | |
break; | |
} else { | |
result.push(element); | |
} | |
} | |
} | |
return result; | |
} | |
/** | |
* Flatten an array of arbitrarily nested arrays of integers into a flat array of integers (recursive implementation). | |
* | |
* @typedef {Array<number|NestedIntegerArray>} NestedIntegerArray | |
* @param {NestedIntegerArray} arr - An array of arbitrarily nested arrays of integers | |
* @return {Array<number>} A flat array of integers | |
* | |
* @example | |
* | |
* flattenShort([[1,2,[3]],4]) -> [1,2,3,4] | |
*/ | |
export function flattenShort(arr: NestedIntegerArray): Array<number> { | |
return arr.reduce( | |
(acc: Array<number>, val) => | |
acc.concat(Array.isArray(val) ? flattenShort(val) : val), | |
[] | |
) as Array<number>; | |
} |
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