This snippet includes two method that helps you working with CPF (brazilian documents).

cpf.py

import random
 
def generate_cpf():
    """Generates a random, valid CPF (brazilian document)
    Reference: http://www.geradorcpf.com/algoritmo_do_cpf.htm
    """
    cpf = [random.randint(1, 9) for i in range(9)]
    weight = range(10, 1, -1)
    weight2 = range(11, 1, -1)
    tmp = [0, 0, 0, 0, 0, 0, 0, 0, 0]
    
    # first verificator digit
    for i in range(9):
        tmp[i] = cpf[i] * weight[i]
    
    rest = sum(tmp) % 11
    
    v1 = 11 - rest if rest >= 2 else 0
    cpf.append(v1)
    tmp.append(0)
    
    # second verificator digit
    for i in range(10):
        tmp[i] = cpf[i] * weight2[i]
    
    rest = sum(tmp) % 11
    v2 = 11 - rest if rest >= 2 else 0
    cpf.append(v2)
    
    # Return the cpf
    cpf = [str(i) for i in cpf]
    return "{0}.{1}.{2}-{3}".format("".join(cpf[0:3]),
                                    "".join(cpf[3:6]),
                                    "".join(cpf[6:9]),
                                    "".join(cpf[9:11]))
 
def validate_cpf(cpf):
    """Validates a CPF (brazilian document)
    Returns True is the CPF is valid, False otherwise
    Reference: http://www.geradorcpf.com/script-validar-cpf-php.htm
    """
    cpf = cpf.replace(".", "").replace("-", "")
    if len(cpf) != 11:
        return False
    
    tt = 0
    for t in range(9, 11):
        d = 0
        for c in range(0, t):
            d += int(cpf[c]) * ((t + 1) - c)
            tt += 1
        d = ((10 * d) % 11) % 10
                
        if int(cpf[c+1]) != d:
            return False
    return True