My Answer to Ruby Koans about_scoring_project.rb

dice_score.rb

def score(dice)
  score=0

  # find first group of 3 and add score. Break out if we find one since
  # you can't have 2 groups of 3 with only 5 dice.
  for outcome in (1..6)
    if dice.count(outcome) >=3
      score += outcome == 1 ? 1000 : 100 * outcome
      
      # Remove the 3 items we matched.
      3.times do dice.delete_at(dice.index(outcome)) end 
      break
    end
  end

  # now score up what's left.
  for die in dice
    score += 100 if die == 1
    score += 50  if die == 5
  end

  score
end