Created
August 21, 2018 08:47
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| class Solution(object): | |
| def numDistinctIslands(self, grid): | |
| """ | |
| :type grid: List[List[int]] | |
| :rtype: int | |
| """ | |
| def get_island(oi, oj, grid): | |
| lands = [] | |
| def dfs(i, j, grid): | |
| if i < 0 or j < 0: return | |
| if i >= len(grid) or j >= len(grid[0]): return | |
| if grid[i][j] == 0: return | |
| grid[i][j] = 0 | |
| lands.append( (str(i-oi), str(j-oj)) ) | |
| dfs(i+1, j, grid) | |
| dfs(i-1, j, grid) | |
| dfs(i, j+1, grid) | |
| dfs(i, j-1, grid) | |
| dfs(oi, oj, grid) | |
| return '|'.join([','.join(l) for l in lands]) | |
| count = 0 | |
| found_islands = {} | |
| for i, row in enumerate(grid): | |
| for j, cell in enumerate(row): | |
| if cell == 1: | |
| # print i, j | |
| island = get_island(i, j, grid) | |
| if island not in found_islands: | |
| found_islands[island] = 1 | |
| count += 1 | |
| # print found_islands | |
| return count |
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