Created
June 11, 2020 01:46
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# Definition for singly-linked list. | |
# class ListNode: | |
# def __init__(self, val=0, next=None): | |
# self.val = val | |
# self.next = next | |
class Solution: | |
def mergeKLists(self, lists: List[ListNode]) -> ListNode: | |
self.lists = lists | |
if len(lists) == 0: | |
return None | |
return self._merge(0, len(lists) - 1) | |
def _merge(self, begin, end) -> ListNode: | |
if begin == end: | |
return self.lists[begin] | |
if (end - begin) == 1: | |
return self.combine(self.lists[begin], self.lists[end]) | |
middle = begin + (end - begin) // 2 | |
return self.combine( | |
self._merge(begin, middle), | |
self._merge(middle + 1, end) | |
) | |
def combine(self, A: ListNode, B: ListNode) -> ListNode: | |
node = ListNode() | |
current_node = node | |
while A is not None and B is not None: | |
if B.val < A.val: | |
new_node = ListNode(val=B.val) | |
B = B.next | |
else: | |
new_node = ListNode(val=A.val) | |
A = A.next | |
current_node.next = new_node | |
current_node = new_node | |
if A is not None: | |
current_node.next = A | |
if B is not None: | |
current_node.next = B | |
return node.next | |
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