Python: Human readable file size

size.py

def sizeof_fmt(num, suffix='o'):
    """Readable file size

    :param num: Bytes value
    :type num: int
    :param suffix: Unit suffix (optionnal) default = o
    :type suffix: str
    :rtype: str
    """
    for unit in ['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z']:
        if abs(num) < 1024.0:
            return "%3.1f %s%s" % (num, unit, suffix)
        num /= 1024.0
    return "%.1f%s%s" % (num, 'Yi', suffix)

Thanks!

I prefer a non looping solution, with something like:

def sizeof_fmt(num, suffix='B'):
    magnitude = int(math.floor(math.log(num, 1024)))
    val = num / math.pow(1024, magnitude)
    if magnitude > 7:
        return '{:.1f}{}{}'.format(val, 'Yi', suffix)
    return '{:3.1f}{}{}'.format(val, ['', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi'][magnitude], suffix)

Спасибо(Thanks)!

I got tired of rewriting these little functions from scratch, now I just import my library. For maximum convenience, it works with str.format() support. It has all the sizes in NIST/IEC and SI units and conventional nonstandard units.

• https://github.com/aphor/datasize
• https://pypi.org/project/datasize/

>>> from datasize import DataSize
>>> 'My new {:GB} SSD really only stores {:.2GiB} of data.'.format(DataSize('750GB'),DataSize(DataSize('750GB') * 0.8))
'My new 750GB SSD really only stores 558.79GiB of data.'