Skip to content

Instantly share code, notes, and snippets.

@ceberly
Last active November 13, 2023 17:31
Show Gist options
  • Save ceberly/d35e1ca2c385fdd0ba2d2cc6c62d2909 to your computer and use it in GitHub Desktop.
Save ceberly/d35e1ca2c385fdd0ba2d2cc6c62d2909 to your computer and use it in GitHub Desktop.
Row vs. Column access patterns
#include <assert.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define NUM_RECORDS 1000000
#define NUM_QUERIES 1000 // number of queries to run in a row
#define LOCATION_ID 42 // for the by_location queries
struct User {
int id;
char name[255];
int birth_location_id;
int time_of_birth;
};
struct ColDB {
int *id;
char *name; // store the names contiguously to mimic row db
int *birth_location_id;
int *time_of_birth;
} col_db;
// row oriented DB is just an array of users.
struct User *row_db;
struct ColDB col_db;
static void setup(void) {
row_db = malloc(sizeof(struct User) * NUM_RECORDS);
assert(row_db != NULL);
col_db.id = malloc(sizeof(int) * NUM_RECORDS);
col_db.name = malloc(255 * NUM_RECORDS);
col_db.birth_location_id = malloc(sizeof(int) * NUM_RECORDS);
col_db.time_of_birth = malloc(sizeof(int) * NUM_RECORDS);
srand((unsigned int)time(NULL));
for (int i = 0; i < NUM_RECORDS; i++) {
int id = abs(rand());
int l = abs(rand()) % 100; // make some duplicate birth locations...
int t = abs(rand()) % 86400; // seconds in a day
row_db[i].id = id;
row_db[i].name[32] = '\0'; // just so we can print the names
row_db[i].birth_location_id = l;
row_db[i].time_of_birth = t;
col_db.id[i] = id;
col_db.name[i * 255 + 32] = '\0';
col_db.birth_location_id[i] = l;
col_db.time_of_birth[i] = t;
}
}
static size_t rusers_by_location(struct User *results) {
size_t count = 0;
for (int i = 0; i < NUM_RECORDS; i++) {
struct User u = row_db[i];
if (u.birth_location_id == LOCATION_ID) {
results[count++] = u;
}
}
return count;
}
static size_t cusers_by_location(struct User *results) {
size_t count = 0;
for (int i = 0; i < NUM_RECORDS; i++) {
if (col_db.birth_location_id[i] == LOCATION_ID) {
struct User u = {
.id = col_db.id[i],
.birth_location_id = col_db.birth_location_id[i],
.time_of_birth = col_db.time_of_birth[i]
};
memcpy(u.name, col_db.name + (i * 255), 255);
results[count++] = u;
}
}
return count;
}
static int cmax_time_of_birth(void) {
int result = 0;
for (int i = 0; i < NUM_RECORDS; i++) {
int t = col_db.time_of_birth[i];
if (t > result)
result = t;
}
return result;
}
static int rmax_time_of_birth(void) {
int result = 0;
for (int i = 0; i < NUM_RECORDS; i++) {
int t = row_db[i].time_of_birth;
if (t > result)
result = t;
}
return result;
}
int main(int argc, char **argv) {
setup();
int c, r = 0;
size_t result_count = 0;
struct User *results = malloc(sizeof(struct User) * NUM_RECORDS);
assert(results != NULL);
time_t start = time(NULL);
for (int i = 0; i < NUM_QUERIES; i++) {
c = cmax_time_of_birth();
}
printf("elapsed: %lds\t cmax_time_of_birth: %d\n", time(NULL) - start, c);
start = time(NULL);
for (int i = 0; i < NUM_QUERIES; i++) {
r = rmax_time_of_birth();
}
printf("elapsed: %lds\trmax_time_of_birth: %d\n", time(NULL) - start, r);
start = time(NULL);
for (int i = 0; i < NUM_QUERIES; i++) {
result_count = rusers_by_location(results);
}
printf("elasped: %lds records for rusers_by_location count: %ld\n",
time(NULL) - start, result_count);
start = time(NULL);
for (int i = 0; i < NUM_QUERIES; i++) {
result_count = cusers_by_location(results);
}
printf("elasped: %lds records for cusers_by_location count: %ld\n",
time(NULL) - start, result_count);
return EXIT_SUCCESS;
}
default:
gcc -O0 -g3 -Wall -Wextra -Wconversion -Wdouble-promotion \
-Wno-unused-parameter -Wno-unused-function -Wno-sign-conversion \
main.c
format:
clang-format -i main.c
# Output on my Intel i5 NUC:
# The corresponding SQL queries are roughly this:
#
# max_time_of_birth:
# SELECT MAX(time_of_birth) FROM users;
#
# users_by_location:
# -- Originally this was just supposed to select users in location "42"
# -- but I had to add extra lookups to try to break the cache on the column-based data structure.
# -- So let's call it:
# "select users from location 42 who were born in the first half of the day and aren't the super user"
# SELECT COUNT(1) FROM users WHERE location = 42 AND time_of_birth < 40000 AND id != 1
./a.out
elapsed: 0s cmax_time_of_birth: 86399
elapsed: 5s rmax_time_of_birth: 86399
elasped: 23s records for rusers_by_location count: 9975
elasped: 2s records for cusers_by_location count: 9975
@ceberly
Copy link
Author

ceberly commented Nov 6, 2023

One more thing, it should be pretty clear that accessing another whole sector of a disk, especially a spinning disc, to get the other parts of the record's data would be significantly slower than doing it in memory (obviously). Also, this experiment was done on an nvme drive which maybe starts to segue into why ssd and nvme optimized db techniques are becoming popular

@vegarsti
Copy link

vegarsti commented Nov 11, 2023

Great experiment! Thanks!

I get somewhat different results (smaller difference):

$ ./a.out
elapsed: 1s      cmax_time_of_birth: 86399
elapsed: 9s     rmax_time_of_birth: 86399
elasped: 13s records for rusers_by_location count: 10156
elasped: 4s records for cusers_by_location count: 10156

I'm on an M1 Mac with 16GB RAM, which has an SSD, not NVMe.

@eatonphil
Copy link

What is the point of storing anything in the results struct? When you do results[count++] = u?

@eatonphil
Copy link

I don't think your experiment is incorrect. I think that the row-wise storage only really helps when you must iterate over all data and/or where you must return a large amount of data.

Here is my version. https://gist.github.com/eatonphil/c2948f65d216a9ad3667801578154eee

@ceberly
Copy link
Author

ceberly commented Nov 12, 2023

Nice, thank you. I am working on an updated version as well that shows more clearly what I was getting at (which your's does as well), since this got a lot of traffic

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment