for (let i = 1; i <= 100; i++) {
if (i % 3 === 0 && i % 5 === 0) {
console.log('fizzbuzz')
} else if (i % 5 === 0) {
console.log('buzz')
} else if (i % 3 === 0) {
console.log('fizz')
} else {
console.log(i)
}
}
This was the fizzbuzz solution for the mock interview week at TIY.