Check iO - The Flat Dictionary

flat_dict

def flatten(dictionary):
    stack = [((), dictionary)]
    result = {}
    while stack:
        path, current = stack.pop()
        for k, v in current.items():
            if isinstance(v, dict):
                stack.append((path + (k,), v))
            else:
                result["/".join((path + (k,)))] = v
                
        if len(current) == 0: 
                result["/".join(path)] = ""
    return result