Python script that checks the HTTP status code of an URL. You have to write a list of URLs (url_list.csv), with the desired status code on the second column (if the second column is empty it takes a 200 like default value). You can use this script for automatic testing some URLs of your internal/external environment

url_check.py

#!/usr/bin/env python

import requests

file = "url_list.csv"

with open(file, 'r') as f:
  for line in f:
    line += ' '
    url = line.split(' ')[0].strip()
    statusCode = line.split(' ')[1].strip()
    if not statusCode:
      statusCode = '200'

    r = requests.get(url)

    if r.status_code == int(statusCode):
      print '[INFO] ' + url + ' passed the test'
    else:
      print '[ERROR] ' + url + ' return ' + str(r.status_code) + ' instead of ' + str(statusCode)

Example CSV:

https://www.google.com/ 200
https://www.facebook.com/foobar424raboof
http://otherexampleurl.com/ 404
https://otherhttpsexampleurl.com/ 503