get dynamic upload path and slugify in Django

get_upload_path.py

from django.db import models
from django.utils.text import slugify

class Document(models.Model):
    def get_upload_path(self, filename):
        """
        Returns the upload path for docs
        """
        filename = filename.split('.')
        extension = filename.pop()
        name = ''.join(filename)
        return "documents/%s/%s.%s" % (self.post.pk, slugify(name), extension)

    document_file = models.FileField(upload_to=get_upload_path)

Thanks for the example, but if you don't like hard coding things, you should probably use methods from os.path:

def get_upload_path(self, filename):
    name, ext = os.path.splitext(filename)
    return os.path.join('documents', self.post.pk, slugify(name), ext)

ironhouzi's solution worked almost perfectly for me, but I had to fix a couple of things (casting to string and concatenating the extension), here is my version:

    def get_upload_path(self, filename):
        name, ext = os.path.splitext(filename)
        return os.path.join('documents', str(self.post.pk), slugify(name) + ext)