Created
June 23, 2014 09:05
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[CC150][2.7] Implement a function to check if a linked list is a palindrome.
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import java.util.LinkedList; //LinkedList in Java is double-linked list | |
import java.util.ListIterator; | |
import java.util.Stack; | |
public class solution { | |
public static<T> boolean isPalindrome(LinkedList<T> list) { | |
if (list == null) throw new IllegalArgumentException(); | |
Stack<T> reverse = new Stack<T>(); | |
int N = 0; | |
for (T element : list) { | |
reverse.add(element); | |
N++; | |
} | |
ListIterator<T> iter = list.listIterator(); | |
for (int i = 0; i < N/2; i++) { | |
if (!iter.next().equals(reverse.pop())) | |
return false; | |
} | |
return true; | |
} | |
public static void main(String[] args) { | |
// TODO Auto-generated method stub | |
LinkedList<Integer> test = new LinkedList<Integer>(); | |
test.add(1); | |
System.out.println(test); | |
if (solution.isPalindrome(test)) | |
System.out.println("Yes"); | |
else System.out.println("No"); | |
test.add(2); | |
System.out.println(test); | |
if (solution.isPalindrome(test)) | |
System.out.println("Yes"); | |
else System.out.println("No"); | |
test.add(2); | |
System.out.println(test); | |
if (solution.isPalindrome(test)) | |
System.out.println("Yes"); | |
else System.out.println("No"); | |
test.add(1); | |
System.out.println(test); | |
if (solution.isPalindrome(test)) | |
System.out.println("Yes"); | |
else System.out.println("No"); | |
} | |
} |
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