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March 25, 2019 05:05
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https://twitter.com/Cshearer41/status/1103717536921800704 | |
Let a, b, c be the triangles, smallest to largest. | |
Observations from the illustration about the relative triangle sizes: | |
side b = 2 * height a [observation ab] | |
side c = 2 * height b [observation bc] | |
Let w be the rectangle's width and let h be its height. | |
Observations about the rectangle's relationship to the triangles: | |
w = side c [observation w] | |
h = height a + height c [observation h] | |
Let k = (sqrt 3) / 4 | |
Facts about any equilateral triangle t: | |
area t = k * (side t)^2 [area fact] | |
height t = 2k * side t [height fact] | |
Obtaining an expression for (side b) in terms of (side a): | |
side b = 2 * height a Restatement of [observation ab] | |
= 2 * (2k * side a) Substituting [height fact] | |
= 4k * side a [lemma ab] | |
Obtaining an expression for (side c) in terms of (side b): | |
side c = 2 * height b Restatement of [observation bc] | |
= 2 * (2k * side b) Substituting [height fact] | |
= 4k * side b [lemma bc] | |
Obtaining an expression for (side c) in terms of (side a): | |
side c = 4k * side b Restatement of [lemma bc] | |
= 4k * (4k * side a) Substituting [lemma ab] | |
= 16 * k^2 * side a [lemma ac] | |
Obtaining an expression for the total area of the triangles in terms of (side a): | |
total triangle area | |
= (area a) | |
+ (2 * area b) | |
+ (area c) | |
= k * (side a)^2 Substituting [area fact] 3 times | |
+ 2k * (side b)^2 | |
+ k * (side c)^2 | |
= k * ( side a )^2 | |
+ 2k * ( 4k * side a )^2 Substituting [lemma ab] | |
+ k * ( 16 * k^2 * side a )^2 Substituting [lemma ac] | |
= k * (side a)^2 | |
+ 32 * k^3 * (side a)^2 | |
+ 256 * k^5 * (side a)^2 | |
= (k + (32 * k^3) + (256 * k^5)) [triangle area lemma] | |
* (side a)^2 | |
Obtaining an expression for the height of the rectangle in terms of (side a): | |
h = (height a) + (height c) Restatement of [observation h] | |
= (2 * k * side a) Substituting [height fact] 2 times | |
+ (2 * k * side c) | |
= (2 * k * side a) | |
+ (2 * k * (16 * k^2 * side a)) Substituting [lemma ac] | |
= (2k * side a) | |
+ (32 * k^3 * side a) | |
= (2k + (32 * k^3)) * side a [rectangle height lemma] | |
Obtaining an expression for the area of the rectangle in terms of (side a): | |
rectangle area | |
= w * h | |
= side c Substituting [observation w] | |
* (2k + (32 * k^3)) * side a Substituting [rectangle height lemma] | |
= 16 * k^2 * side a Substituting [lemma ac] | |
* (2k + (32 * k^3)) * side a | |
= 16 * k^2 * (2k + (32 * k^3)) * (side a)^2 | |
= ( (32 * k^3) + (512 * k^5) ) * (side a)^2 [rectangle area lemma] | |
answer | |
= total triangle area | |
/ rectangle area | |
= ( ( k + (32 * k^3) + (256 * k^5) ) * (side a)^2 ) Substituting [triangle area lemma] | |
/ ( ( (32 * k^3) + (512 * k^5) ) * (side a)^2 ) Substituting [rectangle area lemma] | |
= ( k + (32 * k^3) + (256 * k^5) ) Simplify fraction | |
/ ( (32 * k^3) + (512 * k^5) ) | |
= 2/3 Wolfram Alpha |
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