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Replace widget
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/** | |
* Panel that wraps a GWT simple panel to be replaced by the widgetToAttach. This will make sure that the DIV element | |
* is being replaced rather than having the widget inserted in it. | |
* <p/> | |
* The result of this will be to have a better, cleaner, dom. | |
*/ | |
public class ReplacePanel implements IsWidget, HasOneWidget { | |
static class WrongParentTypeException extends RuntimeException { | |
public WrongParentTypeException(String message) { | |
super(message); | |
} | |
} | |
private IsWidget widget; | |
public ReplacePanel() { | |
widget = new SimplePanel(); | |
} | |
@Override | |
public Widget asWidget() { | |
return widget.asWidget(); | |
} | |
@Override | |
public Widget getWidget() { | |
return widget.asWidget(); | |
} | |
@Override | |
public void setWidget(Widget widgetToAttach) { | |
Widget parentAsWidget = widget.asWidget().getParent(); | |
if (!(parentAsWidget instanceof HTMLPanel)) { | |
throw new WrongParentTypeException("The parent of ReplacePanel must be of type HTMLPanel"); | |
} | |
HTMLPanel parent = (HTMLPanel) parentAsWidget; | |
parent.addAndReplaceElement(widgetToAttach, widget.asWidget().getElement()); | |
widget = widgetToAttach; | |
} | |
@Override | |
public void setWidget(IsWidget widget) { | |
setWidget(widget.asWidget()); | |
} | |
} |
Just throw the exception inside the setWidget() method
and you don't detach logically the old widget
Yes, that is done through the addAndReplace of the parent html panel
you right !
LGTM !
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This code is called when the widget is detached and the parent will be null and the exception will be thrown.