possibleSums

answer.js

function solution(coins, quantity) {
  let s = new Set([0]);
  for (let i in coins) {
    for (let entry of [...s]) {
      for (let j = quantity[i]; j; ) {
        s.add(coins[i] * j-- + entry);
      }
    }
  }
  return s.size - 1;
}