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DAY9 - Dynamic Programming - Maximum Subarray Solution
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// top-down approach | |
function maxSubarray(arr) { | |
const memo = {}; | |
let answer = Number.MIN_VALUE; | |
function _maxSubarray(arr, i) { | |
// base case | |
if (arr.length === 0) return 0; | |
if (i === 0) return arr[0]; | |
// induction case | |
if (memo[i]) return memo[i]; | |
memo[i] = Math.max(_maxSubarray(arr, i - 1) + arr[i], arr[i]); | |
// update answer (find max) | |
if (memo[i] > answer) { | |
answer = memo[i]; | |
} | |
return memo[i]; | |
} | |
_maxSubarray(arr, arr.length - 1); | |
return answer; | |
} | |
// bottom-up approach | |
function maxSubarray(arr) { | |
// base case | |
if (arr.length === 0) return 0; | |
const memo = {}; | |
memo[0] = arr[0]; | |
// induction case | |
let answer = Number.MIN_VALUE; | |
for (let i = 1; i < arr.length; ++i) { | |
memo[i] = Math.max(memo[i-1] + arr[i], arr[i]); | |
if (memo[i] > answer) { | |
answer = memo[i]; | |
} | |
} | |
return answer; | |
} |
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