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- (BOOL)stringContainsEmoji:(NSString *)string { | |
__block BOOL returnValue = NO; | |
[string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock: | |
^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) { | |
const unichar hs = [substring characterAtIndex:0]; | |
// surrogate pair | |
if (0xd800 <= hs && hs <= 0xdbff) { | |
if (substring.length > 1) { | |
const unichar ls = [substring characterAtIndex:1]; | |
const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000; | |
if (0x1d000 <= uc && uc <= 0x1f77f) { | |
returnValue = YES; | |
} | |
} | |
} else if (substring.length > 1) { | |
const unichar ls = [substring characterAtIndex:1]; | |
if (ls == 0x20e3) { | |
returnValue = YES; | |
} | |
} else { | |
// non surrogate | |
if (0x2100 <= hs && hs <= 0x27ff) { | |
returnValue = YES; | |
} else if (0x2B05 <= hs && hs <= 0x2b07) { | |
returnValue = YES; | |
} else if (0x2934 <= hs && hs <= 0x2935) { | |
returnValue = YES; | |
} else if (0x3297 <= hs && hs <= 0x3299) { | |
returnValue = YES; | |
} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) { | |
returnValue = YES; | |
} | |
} | |
}]; | |
return returnValue; | |
} |
In ios7, when input chinese using Pinyin:QWERTY/10 Key, it bugs.
Can I use this code snippet?
@bluefish625 Could you describe what bug exactly concerning Pinyin:QWERTY/10 Key? I cannot find any problem.
@cihancimen , can you please please please please make this in Swift? I really need this! Thanks a lot!
This code doesn't work for all emojis. I have tested it for few emojis. It doesn't work for
Surrogate Pairs : the Unicode standard has reserved the range from U+D800 to U+DFFF for the use of UTF-16
(wiki)
but in this code the range is
if (0xd800 <= hs && hs <= 0xdbff) {
did I missed something?
@swalehapatanwala the reason for the
Anyone using this with iOS 8?
is there C++ code can do this?
Shucks. This doesn't work with all emojis.
works, great ,tks
Yes, this doesn't work with all emojis.
Sorry, have you fixed this issue?
In ios7+, when input chinese using Pinyin:QWERTY/10 Key, it bugs. I found this problem as well, you can change into Chinese input way,I make a breakpoint and found the string change was number with gray color around, I just control the input in should change delegate method, so this code return me yes.
I found the solution, just convert the string first
unichar unicodevalue = [text characterAtIndex:0];
NSString *str = [NSString stringWithCharacters:&unicodevalue length:1];
then use this str to judge
The U+d83e u
Not included
there are some new emojis added in iOS 16.Looks like this code need to be update
Great! We are gonna use this code snippet to remove all emoji characters, those characters shows up ugly on android devices, as a cross platform mobile application we implemented our own emoji solution which looks exactly the same on iOS/Android/Web.