MongoDB equivalent of an SQL query to get the distinct values of a field in a collection including the count of documents which have each distinct value (distinct with count)

mongodb_distinct_count.js

//equivalent of MySQL SELECT COUNT(*) AS cnt, fieldName FROM someTable GROUP BY fieldName;
db.someCollection.aggregate([{"$group" : {_id:"$fieldName", cnt:{$sum:1}}}]);

//as above but ordered by the count descending
//eg: SELECT COUNT(*) AS cnt, fieldName FROM someTable GROUP BY fieldName ORDER BY cnt DESC;
db.someCollection.aggregate([{"$group" : {_id:"$fieldName", cnt:{$sum:1}}}, {$sort:{'cnt':-1}}]);

Thanks!

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thank you

Thanks!