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clippit/gist:2118324

Created March 19, 2012 16:32
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Play a 24 Game with four 0s
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gistfile1.c
#include <stdio.h>
int main() {
printf("%d\n", '0'/(('0'+'0')/'0'));
printf("%d\n", '0'>>'0'/'0'+0);
printf("%d\n", -~-~-~-~-~-~0-~-~-~-~-~-~0-~-~-~-~-~-~0-~-~-~-~-~-~0);
return 0;
}
@deltamaster
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I love the third solution!
0's can be put after any '~' I like.

@deltamaster
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printf("%d\n", ((-0<<-0)+-0)<<---0);
printf("%d\n", ((!0<<!0)+!0)<<---~0);

@CanoeFZH
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((0 – (~0)) << (0 – (~0))) << ((0 – (~0)) << (0 – (~0))) << (0 – (~0)) | ((0 – (~0)) << (0 – (~0))) << ((0 – (~0)) << (0 – (~0)))
(((0 - (~0)) << (0 - (~0))) | (0 - (~0))) << (((0 - (~0)) << (0 - (~0))) | (0 - (~0)))
'0' >> (0 - (~0))

@deltamaster
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Oops, only 4 zeros available...

@CanoeFZH
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O_0... I have just forgot that rule..

@zengqu
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zengqu commented Mar 23, 2012

printf("%d\n",('0'-0)/(printf("%c",0) + printf("%c",0)));

@topin27
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topin27 commented Mar 26, 2012

3 zeros is enough~

@zhangjiantao
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2 zeros is enough~~
'0'>>!0

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