Skip to content

Instantly share code, notes, and snippets.

Embed
What would you like to do?
Parse RSS feed as JSON from client using Google API
var rssUrl = "http://www.exploit-db.com/rss.xml";
function parseRSS(url, callback) {
$.ajax({
url: document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=10&callback=?&q=' + encodeURIComponent(url),
dataType: 'json',
success: function(data) {
callback(data.responseData.feed.entries);
}
});
}
html = "";
parseRSS(rssUrl, function(rss) {
for(i = rss.length-1; i >=0; i--) {
html += "<p><a href='" + rss[i].link + "'>" + rss[i].title + "</a></p>";
}
$("div#target").html(html);
});
@djprmf
Copy link

djprmf commented Jan 21, 2016

@molayli
Copy link

molayli commented Feb 11, 2017

here is an updated version using rss2json.com api

<html>
<head>
  <title>GetRSSFeed</title>
</head>
<body>
<div id="target"></div>

<script src="https://code.jquery.com/jquery-2.2.4.min.js" ></script>
<script>
  var rssUrl = "http://www.exploit-db.com/rss.xml";
  function parseRSS(url, callback) {
    $.ajax({
      url: 'https://api.rss2json.com/v1/api.json?rss_url=' + encodeURIComponent(url),
      dataType: 'json',
      success: function(data) {
        callback(data);
      }
    });
  }
  html = "";
  parseRSS(rssUrl, function(rss) {
      var items = rss.items;
      for(i = items.length-1; i >=0; i--) {
            html += "<p><a href='" + items[i].link + "'>" + items[i].title + "</a></p>";  
      }
    $("div#target").html(html);
  });
</script>
</body>
</html>

@cmbaughman
Copy link
Author

cmbaughman commented Oct 12, 2018

That's awesome! Thanks everyone!

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment