Skip to content

Instantly share code, notes, and snippets.

@coci
Created March 18, 2020 08:37
Show Gist options
  • Star 0 You must be signed in to star a gist
  • Fork 0 You must be signed in to fork a gist
  • Save coci/83ef277a0608e7c39c51b4d7d996a1c3 to your computer and use it in GitHub Desktop.
Save coci/83ef277a0608e7c39c51b4d7d996a1c3 to your computer and use it in GitHub Desktop.
access value from thread
import threading
import Queue
import timeit
q = Queue.Queue()
number = 5
t1 = timeit.default_timer()
# Step1: For example, we are running multiple functions normally
result = []
def fun(x):
result.append(x)
return x
for i in range(number):
fun(i)
print result ," # normal result"
print (timeit.default_timer() - t1)
t2 = timeit.default_timer()
#Step2: by using threads and queue
def fun_thrd(x,q):
q.put(x)
return
for i in range(number):
t1 = threading.Thread(target = fun_thrd, args=(i,q))
t1.start()
t1.join()
thrd_result = []
while True:
if not q.empty():
thrd_result.append(q.get())
else:
break
print thrd_result , "# result with threads involved"
print (timeit.default_timer() - t2)
t3 = timeit.default_timer()
#step :3 if you want thread to be run without depending on the previous thread
threads = []
def fun_thrd_independent(x,q):
q.put(x)
return
def thread_indep(number):
for i in range(number):
t = threading.Thread(target = fun_thrd_independent, args=(i,q))
t.start()
threads.append(t)
thread_indep(5)
for j in threads:
j.join()
thread_indep_result = []
while True:
if not q.empty():
thread_indep_result.append(q.get())
else:
break
print thread_indep_result # result when threads are independent on each other
print (timeit.default_timer() - t3)
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment