python bidirectional search

example_bi_search.py

# Implementation https://stackoverflow.com/questions/54437905/bidirectional-search using deque

class Node:
    def __init__(self, val, neighbors=[]):
        self.val = val
        self.neighbors = neighbors
        self.visited_right = False  # whether the node was reached by the BFS that started from source
        self.visited_left = False  # whether the node was reached by the BFS that started from destination
        self.parent_right = None  # used for retrieving the final path from source to the meeting point
        self.parent_left = None  # used for retrieving the final path from the meeting point to destination


# class Queue:
#    pass  # implement it yourself
from collections import deque

def bidirectional_search(s, t):
    def extract_path(node):
        """return the path when both BFS's have met"""
        node_copy = node
        path = []

        while node:
            path.append(node.val)
            node = node.parent_right
            
        path.reverse()
        del path[-1]  # because the meeting node appears twice
            
        while node_copy:
            path.append(node_copy.val)
            node_copy = node_copy.parent_left
        return path
        
    q = deque([])
    q.append(s)
    q.append(t)
    s.visited_right = True
    t.visited_left = True

    while len(q) > 0:
        n = q.pop()
            
        if n.visited_left and n.visited_right:  # if the node visited by both BFS's
            return extract_path(n)
            
        for node in n.neighbors:
            if n.visited_left == True and not node.visited_left:
                node.parent_left = n
                node.visited_left = True
                q.append(node)
            if n.visited_right == True and not node.visited_right:
                node.parent_right = n
                node.visited_right = True
                q.append(node)

    # not found
    return False

            
n0 = Node(0)
n1 = Node(1)
n2 = Node(2)
n3 = Node(3)
n4 = Node(4)
n5 = Node(5)
n6 = Node(6)
n7 = Node(7)
n0.neighbors = [n1, n5]
n1.neighbors = [n0, n2, n6]
n2.neighbors = [n1]
n3.neighbors = [n4, n6]
n4.neighbors = [n3]
n5.neighbors = [n0, n6]
n6.neighbors = [n1, n3, n5, n7]
n7.neighbors = [n6]
print(bidirectional_search(n0, n4))

Thanks!!!