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//4 outcomes are: | |
var o1 = 'JavaScript wins!'; | |
var o2 = 'You win!'; | |
var o3 = 'A Draw'; | |
var pcChoice = 0; | |
var userChoice = 0; | |
var pcShows = 'none'; | |
var userShows = 'none'; | |
var outcome = 'none'; | |
console.log('Rock Paper Scissors Game in JavaScript'); | |
while (userChoice < 1 || userChoice > 3 || isNaN(userChoice)) { | |
userChoice = prompt('1 = Rock, 2 = Papper, 3 = Scissors'); userChoice = parseInt(userChoice);} | |
if (userChoice === 1){userShows = 'a Rock';} | |
if (userChoice === 2){userShows = 'Paper';} | |
if (userChoice === 3){userShows = 'Scissors';} | |
while (pcChoice < 1 || pcChoice > 3) { | |
pcChoice = Math.floor(Math.random() * 4);} | |
if (pcChoice === 1){pcShows = 'a Rock';} | |
if (pcChoice === 2){pcShows = 'Paper';} | |
if (pcChoice === 3){pcShows = 'Scissors';} | |
//describe the result | |
console.log('PC throws ' + pcShows + ' as you throw ' + userShows + '!'); | |
//decide winner or draw | |
if ((userChoice === 1) && (pcChoice === 1)){outcome = o3;} | |
if ((userChoice === 1) && (pcChoice === 2)){outcome = o1;} | |
if ((userChoice === 1) && (pcChoice === 3)){outcome = o2;} | |
console.log(' '); | |
console.log(outcome); | |
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if someVar has a string value like 'Dave' and you call parseInt(someVar) and if next you call isNaN(someVar) It still returns true. So it looks like parseInt() will not convert all strings to ints and will only do so in cases where the string value, e.g. '2' would be an integer by removing its single quotes. I will check what parseInt() does to a float type for 0.47 and val 0.00, I suspect they become NaN but I don't know.