codecakes

• Pattern match.
• Keep consistent level of abstraction per function.
• Don't mix pure functions with IO functions. Segregate.
• Build upon ubiquituous domain language.
• Define Interfaces for service layer around infrastructure and application.
• Partial function composition == Dependency Injection. But it is not a preferred functional pattern.
• Don't YAGNI
• If you find yourself passing parameters and adding conditional..the abstraction is incorrect.
• Build upon these foundational low-level architectural design patterns:
• Value objects, Business Domains, Service Layers

codecakes

HA principles: CAP done right

• Design in isolation (Partition)
  • 2 business modules must communicate over message pattern. They are not considered business modules if one requires the other, in which case they don’t need to communicate over messages if a business process has to die, all interconnected business modules must die
  • process are stateless
  • fault tolerant implies scalability implies concurrency and concurrent business processes
• Availability
  • its better to die on fault and restart, then drag and build up the pile of error
• when a process dies, fault detection and communicating fault is important

codecakes

defmodule ToHex do

  @hex_base 16

  def to_hex(0), do: 0

  def to_hex(num) when is_number(num) do
    div(num, @hex_base)
    |> IO.inspect
    |> then(& {to_hex(&1), rem(num, @hex_base)})

codecakes

x = [1,2,3]
if len(x) < 3:
  return x
else:
  return [4,5,6]

codecakes

from numbers import Number


def selection_sort(arr: list[Number]) -> list[Number]:
    n = len(arr)
    swap_index = 0
    for start_idx, start_num in enumerate(arr):
        min_num = float('inf')
        for idx in range(start_idx, n):
            num = arr[idx]

codecakes

# ==================================== #

VOWELS = ['a', 'e', 'i', 'o', 'u', "A", "E", "I", "O", "U"]


def calc_epigram(sentence: str) -> int:
    return sum(ord(char) if char not in VOWELS else -ord(char) for char in filter(lambda x: x.isalpha(), sentence))


assert (calc_epigram("why and how")) == 569

codecakes

# ================ Palindrome ==================== #

def is_num_palindrome(num: int) -> bool:
    num = abs(num)
    while num > 9:
        exponent = math.floor(math.log10(num))
        msb, remainder = divmod(num, 10 ** exponent)
        num, lsb = divmod(remainder, 10)
        if msb != lsb:
            return False

codecakes

import math

# ================ Int to Roman ==================== #
RomanMapping = {
    1: 'I',
    4: 'IV',
    5: 'V',
    9: 'IX',
    10: 'X',
    40: 'XL',

codecakes

"""
Given two strings s and t of lengths m and n respectively, 
return the minimum window substring of s such that every character in t (including duplicates) 
is included in the window. 
If there is no such substring, return the empty string "".


A substring is a contiguous sequence of characters within the string.

This is fucking hard.

codecakes

"""Given two strings s and p, return an array of all the start indices of p's anagrams in s. 
You may return the answer in any order.

An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, 
typically using all the original letters exactly once.
"""


from collections import Counter